Mrs. Beck paid a total of $34 for 4 identical bowls and 2 identical plates. A bowl cost $4 more than a plate. How much did she pay for each bowl?

4b+2p = 34

p = b-4

4 b + 2(b-4) = 34

4 b + 2 b - 8 = 34

6 b = 42

b = 7

b = 7

4(7) + 2p = 34
28+2p = 34
-28. -28

2p = 6

p = 6/2
p= 3

To find out how much Mrs. Beck paid for each bowl, let's analyze the given information.

Let's assume the cost of a plate is represented by 'x'. Therefore, the cost of a bowl is 'x + 4' as given in the problem.

Mrs. Beck bought 4 identical bowls, so the total cost of the bowls is 4 times the cost of a single bowl, which is 4 * (x + 4).

Similarly, she also bought 2 identical plates, so the total cost of the plates is 2 times the cost of a single plate, which is 2 * x.

According to the problem, the total cost of the bowls and plates combined is $34.

Therefore, we can set up the equation:
4 * (x + 4) + 2 * x = 34

Now, let's solve this equation to find the value of x and ultimately calculate the cost of each bowl.

1. Distribute the multiplication:
4x + 16 + 2x = 34

2. Combine like terms:
6x + 16 = 34

3. Subtract 16 from both sides of the equation to isolate the variable:
6x = 34 - 16

4. Simplify:
6x = 18

5. Divide both sides of the equation by 6 to solve for x:
x = 18 / 6
x = 3

So, the cost of a plate is $3.

To find the cost of a bowl, which is 'x + 4' in this case:
Bowl cost = 3 + 4
Bowl cost = $7

Therefore, Mrs. Beck paid $7 for each bowl.