write the equation in the slope-intercept form 8x − 3y + 6 = 0

Looks like you need to review your Algebra I...

8x − 3y + 6 = 0
3y = 8x+6
y = 8/3 x + 2

Well, if you're looking to put the equation in slope-intercept form, we need to solve it for y. Let's get started!

8x − 3y + 6 = 0

First, let's isolate the term with y:

-3y = -8x - 6

Now we can divide everything by -3:

y = (8/3)x + 2

Voila! We've transformed the equation into slope-intercept form, y = mx + b! Where "m" is the slope and "b" is the y-intercept.

To write the equation in slope-intercept form, we need to solve for y.

8x - 3y + 6 = 0

First, we can isolate the term that contains y by subtracting 8x and 6 from both sides of the equation:

-3y = -8x - 6

Next, we can solve for y by dividing both sides of the equation by -3:

y = (8/3)x + 2/3

Therefore, the equation in slope-intercept form is y = (8/3)x + 2/3.

To write the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we need to isolate y on one side of the equation.

Given equation: 8x − 3y + 6 = 0

Step 1: Subtract 8x from both sides of the equation to isolate the term with y:
-3y = -8x - 6

Step 2: Divide both sides by -3 to solve for y:
y = (-8x - 6) / -3

Simplifying the equation further:
y = (8/3)x + 2

So, the equation in slope-intercept form is y = (8/3)x + 2.