How long will it take a sled to reach the bottom of a hill, if it accelerates at 5.60m/s^2 and has a final velocity at the bottom of the hill of 42.3km/h?
V = Vo + a*t.
V = 42300m/3600s = 11.75 m/s.
Vo = 0, a = 5.60 m/s^2, t = ?.
To calculate the time it will take for the sled to reach the bottom of the hill, we can use the equations of motion.
First, let's convert the final velocity from km/h to m/s. We know that 1 km/h is equal to 0.27778 m/s, so the final velocity is:
42.3 km/h * 0.27778 m/s = 11.75 m/s
Next, we can use the equation:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. In this case, we have the final velocity (11.75 m/s), the acceleration (5.60 m/s^2), and we want to find the time t.
Rearranging the equation, we get:
t = (v - u) / a
Since the sled starts from rest (u = 0 m/s), the equation simplifies to:
t = v / a
Plugging in the values:
t = 11.75 m/s / 5.60 m/s^2 ≈ 2.098 seconds
Therefore, it will take approximately 2.098 seconds for the sled to reach the bottom of the hill.