The positive difference between two consecutive odd numbers is 336. compute the larger of the two squares. But my solution was(n+1)^2-n^2=336. And. =2n+1=336. ,2n=335 where. I had n=335/2. Here igot stuck on solving the larger of the two squares. And unknown if my answer is incorrect
To solve this problem, your approach of setting up a system of equations is correct.
Let's go through the steps to find the solution:
1. Let's assume the smaller odd number is represented by n.
2. The next odd number will be represented by (n + 2) since it is consecutive.
3. The positive difference between these two numbers gives us the equation: (n + 2) - n = 336.
4. Simplifying the equation gives us: 2 = 336.
5. However, this equation is not possible, and that's where you got stuck.
The issue in your calculations lies in the equation simplification at step 4. Let's correct it:
1. Start with the equation: (n + 2) - n = 336.
2. Simplify: 2 = 336.
3. To solve for n, subtract 2 from both sides: 2 - 2 = 336 - 2.
This gives us 0 = 334, which is incorrect.
Since this equation doesn't make sense, we need to find an alternative approach to solve the problem.
Alternative approach:
1. Suppose the smaller odd number is represented as n.
2. Then, the larger odd number will be represented as (n + 2) since they are consecutive.
3. We know that the positive difference is 336, so we have the equation: (n + 2) - n = 336.
4. Simplify the equation: 2 = 336.
5. As we have discussed earlier, this equation doesn't have a valid solution.
From this, we can conclude that there is no valid solution to this problem.
sniff my bum
Your answer is clearly incorrect, since you want integers. The problem is that odd numbers differ by 2, so
(n+2)^2-n^2 = 336
now it should work better.