A brass is 2m long at a certain temperature.what is its length for a temperature rise of 100k if the expansivity of brass is 18×10^6k^1
I am asking
deltaL=2*18E-6*100=12*18*E-4=.0216m
new length=2+deltaL
Thanks very much but meaning of deltaL
To find the change in length of the brass, we can use the formula:
ΔL = α * L0 * ΔT
Where:
ΔL is the change in length of the brass
α is the expansivity of brass
L0 is the original length of the brass at the given temperature
ΔT is the change in temperature
Given that the expansivity of brass is α = 18 × 10^(-6) K^(-1) and the change in temperature is ΔT = 100 K, we need to find the original length L0.
Since the original length is given as 2 m, we can substitute these values into the formula:
ΔL = (18 × 10^(-6) K^(-1)) * (2 m) * (100 K)
ΔL = 0.036 m
Therefore, the change in length of the brass for a temperature rise of 100 K is 0.036 meters (or 36 mm).