Graph the direct variation y=−1.5x. Using the graph, find:
The value of x when y=−3; 4.5; 6
To graph the direct variation y = -1.5x, we can plot several points on the graph and then connect them to create a straight line.
To find the value of x when y = -3, we can substitute -3 for y in the equation and solve for x:
-3 = -1.5x
To solve for x, divide both sides of the equation by -1.5:
x = -3 / -1.5
x = 2
So, when y = -3, x = 2.
Similarly, to find the value of x when y = 4.5, we substitute 4.5 for y in the equation and solve for x:
4.5 = -1.5x
Dividing both sides by -1.5:
x = 4.5 / -1.5
x = -3
So, when y = 4.5, x = -3.
Lastly, to find the value of x when y = 6, we substitute 6 for y in the equation:
6 = -1.5x
Dividing both sides by -1.5:
x = 6 / -1.5
x = -4
So, when y = 6, x = -4.
Now, we can plot these points on the graph and connect them to visualize the direct variation y = -1.5x.
Well, did you use your graph as instructed?
What did you get?