Using equation only. Show how tetraoxosulphate(IV) can be prepared industrially

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To prepare tetraoxosulfate(IV) industrially, the following equation can be used:

2SO2 + O2 → 2SO3

Here's an explanation of how to derive this equation and the industrial process:

Step 1: Understand the chemical formula of tetraoxosulfate(IV)
The chemical formula of tetraoxosulfate(IV) is SO3. This means it contains one sulfur atom (S) and three oxygen atoms (O).

Step 2: Determine the oxidation state of sulfur in tetraoxosulfate(IV)
The oxidation state of oxygen is usually -2, and since there are three oxygen atoms with a total oxidation state of -6, the oxidation state of sulfur must be +6 for the overall compound to be neutral.

Step 3: Identify the reactants and products for the industrial preparation
For the industrial preparation of tetraoxosulfate(IV), the reactants are sulfur dioxide (SO2) and oxygen gas (O2). The product is tetraoxosulfate(IV) (SO3).

Step 4: Balance the equation
Knowing the reactants and products, we need to balance the equation to ensure that both sides have the same number of atoms of each element.

2SO2 + O2 → 2SO3

This balanced equation shows that two molecules of sulfur dioxide react with one molecule of oxygen gas to produce two molecules of tetraoxosulfate(IV).

Step 5: Interpret the balanced chemical equation
In the industrial process, a mixture of sulfur dioxide and oxygen is passed over a catalyst (such as vanadium pentoxide) at a high temperature (around 400-600°C). The catalyst helps to facilitate the reaction, and the temperature ensures a sufficient reaction rate.

The sulfur dioxide (SO2) and oxygen (O2) combine in the presence of the catalyst to form tetraoxosulfate(IV) (SO3). This reaction is known as the Contact process and is the primary industrial method for producing tetraoxosulfate(IV) on a large scale.

So, by following the balanced equation and understanding the industrial process, you can see how tetraoxosulfate(IV) can be prepared industrially using equation only.