Calculate the vapour density of a triatomic gasX if it's relative atomic mass is 16
triatomic? the Mol mass=48grams
PV=nRT
so vapour density requires a temp, pressure.
so lets do it at STP. one mole
One mole occupies 22.4 L at STP.
density=48/22.4 g/L= 48000mg/22400cm^3=2.14mg/cm^3
=
24
an oxide XO2 has a vapour density constant of 32 . what is the atomic mass of X
To calculate the vapor density of a gas, we need to know the molecular formula of the gas.
Since the gasX is mentioned to be triatomic, it means that the molecule is composed of three atoms.
The relative atomic mass (RAM) of 16 is the average mass of all the atoms in the molecule.
To find the molecular mass of the gasX, we need to determine the mass of each atom in the molecule.
Since the molecule is triatomic, we can assume it contains three atoms of the same element. Let's assume it is composed of three atoms of element Y.
To calculate the molecular mass of gasX, we multiply the relative atomic mass (RAM) by the number of atoms in the molecule:
Molecular mass = RAM * Number of atoms
Molecular mass of gasX = 16 * 3 = 48
Finally, the vapor density is equal to the molecular mass of the gas divided by the relative molecular mass of the standard substance (usually hydrogen or air).
Vapor density = Molecular mass / Relative molecular mass of standard substance.
Let's assume we are comparing it to air, which has a relative molecular mass of approximately 29. So the vapor density of gasX is:
Vapor density = 48 / 29 ≈ 1.655
Therefore, the vapor density of gasX is approximately 1.655.