Construction of triangle ABC IN which AB-7cm BC-13cm and BD-3cm where AD perpendicular BC
We have AD perpendicular to BC.
So triangle ABD is right-angled at D.
AB=7, BD=3, therefore by Pythagoras theorem,
AD=√(AB²-BD²)
=√(7²-3²)
=√40
Construct triangle ABD with the given dimensions. Extend BD to C such that BC=13. Join A and C to complete triangle ABC.
To construct triangle ABC with the given measurements, we will follow these steps:
Step 1: Draw a line segment AB of 7 cm.
Step 2: At point A, draw a perpendicular line AD to AB.
Step 3: On the line AD, measure and mark a point D that is 3 cm away from A.
Step 4: From point D, draw a line segment DB of 3 cm.
Step 5: On the line AB, measure and mark a point C that is 13 cm away from B.
Step 6: Join points C and D with a straight line segment.
Step 7: Label the points of intersection as point C and point D.
Step 8: Triangle ABC has been constructed, with AB measuring 7 cm, BC measuring 13 cm, and BD measuring 3 cm.