1. if one side of a square is increased by 2metres and other side is reduced by 2 metres. a rectangle is formed whose perimeter is 48.find the side of the orignal square.
2(x+2 + x-2) = 48
To solve this problem, we need to use the information given and set up equations based on it. Let's say the side length of the original square is "x" meters.
According to the problem, if one side of the square is increased by 2 meters, it becomes (x + 2) meters. And if the other side is reduced by 2 meters, it becomes (x - 2) meters.
Now we form a rectangle by using these side lengths. The perimeter of a rectangle is calculated by adding the lengths of all four sides.
In this case, the perimeter of the rectangle is given as 48 meters. So we set up the equation:
2(x + 2) + 2(x - 2) = 48
Let's simplify this equation:
2x + 4 + 2x - 4 = 48
4x = 48
Now we can solve for x by dividing both sides of the equation by 4:
4x/4 = 48/4
x = 12
Therefore, the side length of the original square is 12 meters.