A body travels from rest with acceleration 8m/s square . Find its velocity when it has covered a distance of 100m
There is a standard formula for this:
"from rest" means initial velocity = 0
or
V0=0 m/s
Given acceleration, a = 8 m/s²
S = distance travelled = 100 m
Let
V1=final velocity, then the given formula is:
V1²=V0²+2aS
Substitute values of V0, a and S into above equation and solve for V1.
To find the velocity of the body when it has covered a distance of 100m, we can use the equations of motion.
First, let's list down the given values:
- Initial velocity (u) = 0 m/s (since the body starts from rest)
- Acceleration (a) = 8 m/s²
- Distance (s) = 100 m
We need to determine the final velocity (v) of the body.
We can use the third equation of motion:
v² = u² + 2as
Substituting the given values:
v² = (0)² + 2(8)(100)
Simplifying:
v² = 0 + 1600
v² = 1600
Taking the square root of both sides:
v = √1600
v = 40 m/s
Therefore, the velocity of the body when it has covered a distance of 100m is 40 m/s.
To get this result, we used the equation of motion v² = u² + 2as, which relates the final velocity, initial velocity, acceleration, and distance traveled.