It is found that the number of raisins in a box of a popular cereal is normally distributed, with a mean of 133 raisins per box and a standard deviation of 10 raisins. My cereal box has 147 raisins. What is the z-score for this box of cereal?

147 is 1.4 std above the mean, so ...

To find the z-score, we can use the formula:

z-score = (x - mean) / standard deviation

Given that the mean is 133 raisins, the standard deviation is 10 raisins, and the number of raisins in your cereal box is 147, we can plug these values into the formula:

z-score = (147 - 133) / 10

z-score = 14 / 10

z-score = 1.4

Therefore, the z-score for this cereal box is 1.4.

To find the z-score for a box of cereal with 147 raisins, we can use the formula:

z = (x - μ) / σ

where:
- x is the observed value (147 in this case)
- μ is the mean of the distribution (133 in this case)
- σ is the standard deviation of the distribution (10 in this case)

Substituting the values into the formula, we have:

z = (147 - 133) / 10

Simplifying the equation:

z = 14 / 10

z = 1.4

Therefore, the z-score for the box of cereal with 147 raisins is 1.4.