A cube of solid reactant with sides of 1.00 cm² is submerged in a liquid and reacts to form a gas product at an initial rate of 20 mL/s. The solid-liquid interface is 6.0cm² of surface area. If you sliced this cube (like a block of cheese) into 10 slices, and then replaced it in the liquid, predict the initial rate of reaction.

Well, if we're slicing this cube like a block of cheese, does that mean we get to enjoy some cheesy reactions? 🧀

Now, let's get to the slicing business. If we divide the cube into 10 slices, each slice would have a surface area of 0.1 cm².

Since the original cube had a solid-liquid interface of 6.0 cm², and we sliced it into 10 equal-sized slices, the new total surface area in contact with the liquid would be 6.0 cm² * 10 = 60 cm².

To predict the initial rate of reaction, we can use the ratio of the new total surface area to the initial rate of reaction: 60 cm² / 1.00 cm² = 60.

So, the predicted initial rate of reaction for these slices should be 60 times the original rate, which means we're looking at an initial rate of approximately 20 mL/s * 60 = 1200 mL/s.

That's certainly a lot more reaction going on, so prepare for some bubbling chemistry! 🧪💥

To predict the initial rate of reaction when the cube is sliced into 10 equal-sized slices and replaced in the liquid, we need to consider the change in surface area.

1. Start by determining the total surface area of the original cube. Each face of the cube has an area of (1.00 cm)² = 1.00 cm². Since a cube has six faces, the total surface area of the cube is 6 * 1.00 cm² = 6.00 cm².

2. Calculate the surface area of each slice. Since we are slicing the cube into 10 equal-sized slices, the surface area of each slice is 6.00 cm² / 10 = 0.60 cm².

3. The solid-liquid interface is 6.0 cm², which indicates that the cube is completely immersed in the liquid. Since we sliced the cube into 10 equal-sized slices, each slice has the same surface area exposed to the liquid.

4. Therefore, we can assume that the exposed surface area for each slice is 6.0 cm² / 10 = 0.60 cm².

5. Now, we can predict the initial rate of reaction for each slice. Given that the initial rate for the original cube is 20 mL/s, we can determine the initial rate for each slice by multiplying the original rate by the ratio of the exposed surface area (0.60 cm²) to the total surface area of the original cube (6.00 cm²).

Initial rate for each slice = (Exposed surface area of each slice / Total surface area of original cube) * Initial rate of the original cube

Initial rate for each slice = (0.60 cm² / 6.00 cm²) * 20 mL/s

Initial rate for each slice = 0.1 * 20 mL/s

Initial rate for each slice = 2.0 mL/s

Therefore, the predicted initial rate of reaction for each slice, when the cube is sliced into 10 equal-sized slices and replaced in the liquid, is 2.0 mL/s.