A boy had a box of animal crackers. He counted them out and found 20 cookies.
7 elephant cookies
6 tiger cookies
5 monkey cookies
2 zebra cookies
Suppose the boy put all the cookies back into the box and took 1 out without looking.
What is the probability of him choosing..
An elephant?
A tiger?
A monkey?
A zebra?
Does the sum of the probabilities a,b,c and d equal 1?
prob(elephant) = 7/20
prob(tiger) = 6/20
continue ...
add them up to make sure they add up to 1,
they will!
If they don't you messed up
Ty Reiny very much appreciate it : )
To find the probability of choosing a specific type of cookie, we need to divide the number of cookies of that type by the total number of cookies in the box. In this case, we have 20 cookies in total.
a) Probability of choosing an elephant: There are 7 elephant cookies, so the probability is 7/20.
b) Probability of choosing a tiger: There are 6 tiger cookies, so the probability is 6/20.
c) Probability of choosing a monkey: There are 5 monkey cookies, so the probability is 5/20.
d) Probability of choosing a zebra: There are 2 zebra cookies, so the probability is 2/20.
Now let's add up the probabilities and see if they sum to 1:
(7/20) + (6/20) + (5/20) + (2/20) = 20/20 = 1
Yes, the sum of the probabilities a, b, c, and d equals 1, which is expected because the boy can only choose one type of cookie from the box.