Mona's father is thrice as Mona after 12 years his age is just twice of his daughter find their present age?
now:
Mona ---- x
Dad ----- 3x
in 12 years:
Mona = x+12
Dad = 3x+12
3x+12 = 2(x+12)
take over
Mona age be 12 & her father's age be 36
rumpa dey
Please I don't understand
To find out Mona's and her father's present ages, we'll start by assigning variables for their ages.
Let's say Mona's current age is "M" and her father's current age is "F".
It is given that Mona's father is thrice as old as Mona, so we can write the equation:
F = 3M [equation 1]
After 12 years, Mona's age will be M + 12, and her father's age will be F + 12.
According to the problem, after 12 years, Mona's father's age will be twice Mona's age, so we can write the equation:
F + 12 = 2(M + 12) [equation 2]
Now, we can solve equations 1 and 2 simultaneously to find the values of M and F.
First, simplify equation 2 by distributing the 2:
F + 12 = 2M + 24
Substitute the value of F from equation 1 into equation 2:
3M + 12 = 2M + 24
Next, subtract 2M from both sides of the equation:
3M - 2M + 12 = 2M - 2M + 24
Simplify the equation further:
M + 12 = 24
Now, subtract 12 from both sides of the equation:
M + 12 - 12 = 24 - 12
Simplify the equation once more:
M = 12
We've found that Mona's current age is 12.
Now, substitute the value of M = 12 into equation 1 to find Mona's father's current age:
F = 3M
F = 3 * 12
F = 36
So, Mona's present age is 12, and her father's present age is 36.