how many moles are released when 13.2 g of ammonium sulfate 2NH4SO4 is dissolved in water ? I know 13.2 g 2NH4SO4 = .099 moles
ammonium sulfate is (NH4)2SO4 and not what you have.
So if 13.2 g (NH4)2SO4 is 0.088 mols, the you get 0.099 mols SO4^2- and 2*0.099 mols NH4 for a total of ?? mols.
To determine the number of moles released when 13.2 g of ammonium sulfate (NH4)2SO4 is dissolved in water, you need to convert the given mass of the substance into moles.
The molar mass of (NH4)2SO4 can be calculated by summing the atomic masses of the individual elements in the compound. Here's how to do it:
(NH4)2SO4:
- The atomic mass of nitrogen (N) is 14.01 g/mol
- The atomic mass of hydrogen (H) is 1.01 g/mol
- The atomic mass of sulfur (S) is 32.07 g/mol
- The atomic mass of oxygen (O) is 16.00 g/mol
To determine the molar mass of (NH4)2SO4, you multiply the atomic masses by their respective subscripts and sum them up:
Molar mass of (NH4)2SO4 = (2 * atomic mass of N) + (8 * atomic mass of H) + atomic mass of S + (4 * atomic mass of O)
Molar mass of (NH4)2SO4 = (2 * 14.01 g/mol) + (8 * 1.01 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol)
Molar mass of (NH4)2SO4 = 132.14 g/mol
Now that you know the molar mass of (NH4)2SO4 is 132.14 g/mol, you can calculate the number of moles by dividing the given mass of 13.2 g by the molar mass:
Number of moles = mass / molar mass
Number of moles = 13.2 g / 132.14 g/mol
Number of moles = 0.0999 ≈ 0.1 moles
Therefore, 13.2 g of ammonium sulfate, (NH4)2SO4, is approximately equal to 0.1 moles.