We have a heat engine that produces 150 J of heat, does 40 J of work, and emits 110 J into another system. What is the efficiency of the heat engine? (show you work)
if you put 150 in and get 40 out
it is
100(4/15) = 27%
but
it has to get energy from somewhere. It can not "produce" 150 + 40 +110 without putting any energy in. I suspect a typo in the problem description. It does not produce 150 J, it absorbs 150 J
To find the efficiency of a heat engine, we can use the following formula:
Efficiency = (work output / heat input) * 100%
Given that the heat engine produces 150 J of heat (heat input) and does 40 J of work (work output), we can substitute these values into the formula:
Efficiency = (40 J / 150 J) * 100%
Calculating the ratio within the parentheses:
Efficiency = 0.2667 * 100%
Multiplying the decimal by 100%:
Efficiency = 26.67%
Therefore, the efficiency of the heat engine is 26.67%.
To calculate the efficiency of a heat engine, we need to use the formula:
Efficiency = (Useful output energy / Input energy) * 100%.
In this case, the useful output energy is the work done, which is 40 J.
The input energy is the heat supplied to the engine, which is 150 J.
So, the efficiency is:
Efficiency = (40 J / 150 J) * 100%
= (0.2667) * 100%
= 26.67%.
Therefore, the efficiency of the heat engine is 26.67%.