Please Help!!!
Given: A= 10km S30degreesW and B= 15km S40degreesW Find the resulting vector (magnitude and direction) of the combined vectors
Okay. Just so you know...this is a problem my friend gave me and he told me to solve it but I don't know how
Help!!!!!
Tell your friend to break each into s, W components, then add like components, then reolve it back to a single vector.
...I'm 14. He's 19. I need the answer please!!!!!!!!!
Why do you need the answer? Let "your friend" fend for himself.
@Ms. Sue
He's quizzing me and I can't figure it out, I just need help!
He told you how to do it
1. add the south components of each to get the south component of the resultant , S
2. add the west components of each to get the west component of resultant, W
get the magnitude sqrt(S^2+W^2)
tan A =W/S
where A is angle west of south
To find the resulting vector, we need to break down the given vectors A and B into their horizontal (East-West) and vertical (North-South) components. Then, we can add the corresponding components to find the resulting vector.
Let's start by finding the horizontal and vertical components of vector A:
Horizontal component of A (A_x):
To find the horizontal component, we need to find the projection of vector A onto the East-West direction. Since A is directed 30 degrees West from the South, we can consider it as a triangle with the hypotenuse of length 10 km. Therefore, the horizontal component can be calculated using trigonometry:
A_x = A * cos(30 degrees)
Vertical component of A (A_y):
To find the vertical component, we need to find the projection of vector A onto the North-South direction. Since A is directed 30 degrees West from the South, we can consider it as a triangle with the hypotenuse of length 10 km. Therefore, the vertical component can be calculated using trigonometry:
A_y = A * sin(30 degrees)
Now, let's calculate the horizontal and vertical components of vector B using the same approach:
Horizontal component of B (B_x):
To find the horizontal component, we need to find the projection of vector B onto the East-West direction. Since B is directed 40 degrees West from the South, we can consider it as a triangle with the hypotenuse of length 15 km. Therefore, the horizontal component can be calculated using trigonometry:
B_x = B * cos(40 degrees)
Vertical component of B (B_y):
To find the vertical component, we need to find the projection of vector B onto the North-South direction. Since B is directed 40 degrees West from the South, we can consider it as a triangle with the hypotenuse of length 15 km. Therefore, the vertical component can be calculated using trigonometry:
B_y = B * sin(40 degrees)
Now, we can find the resulting vector by adding the corresponding horizontal and vertical components of A and B:
Resultant Horizontal component (R_x) = A_x + B_x
Resultant Vertical component (R_y) = A_y + B_y
To find the magnitude of the resulting vector (R), we can use the Pythagorean theorem:
R = sqrt((R_x)^2 + (R_y)^2)
To find the direction of the resulting vector, we can use trigonometry:
Direction (theta) = arctan(R_x / R_y)
Now, let's plug in the values and calculate the resulting vector magnitude and direction.