We have a heat engine that produces 150 J of heat, does 40 J of work, and emits 110 J into another system. What is the efficiency of the heat engine?

Please don't give me the answer! Just help figure out how to find it! The description for the lesson with this question was 1 paragraph long :/ so I have no idea what to do! Thank you! :)

100(work out/heat in)

the heat out to the other system is lost to this problem. Note that it is 110 which is what is left over after you take 40 out of your 150
see
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/heaeng.html

it PRODUCES 150 J of heat?

Usually one must put heat into an engine to get work out (boil water, burn gas). This is either a typo or a magic trick.

To find the efficiency of a heat engine, you need to use the formula:

Efficiency = (Useful work output / Heat input) × 100%

In this case, the heat input is the total heat produced by the heat engine, which is given as 150 J. The useful work output is the work done by the engine, which is given as 40 J.

So, using the formula:

Efficiency = (40 J / 150 J) × 100%

To find the efficiency, divide the useful work output (40 J) by the heat input (150 J), and multiply the result by 100%. This will give you the efficiency of the heat engine as a percentage.