Find the equation of the line which cuts the y-axis at -3 and is parallel to 4x-y+=0.

Please show working out, thanks.

Parallel to 4x-y+1=0, sorry.

you have a slope (4) and an intercept (-3), so try the slope-intercept form:

y = 4x-3

To find the equation of a line parallel to another line, we need to determine the slope of the given line.

The equation of the given line is in the form "4x - y = 0," where the coefficient of x is the same as the slope of the line. Therefore, the slope of the given line is 4.

Since the line we want to find is parallel to the given line, it will have the same slope of 4.

We also know that the line cuts the y-axis at -3, which means the y-intercept is -3.

Now, we can use the slope-intercept form of a line, which is y = mx + b, where m is the slope and b is the y-intercept.

Plugging in the values, our equation becomes y = 4x - 3.

So, the equation of the line that cuts the y-axis at -3 and is parallel to 4x - y = 0 is y = 4x - 3.