Mari is 3 times older then nandhini after ten years the sum of thare ages will be 80 find the present age???
M = 3N
(M+10) + (N+10) = 80
Substitute 3N for M in the second equation and solve for N. Insert that value into the first equation to solve for M. Check by putting both values into the second equation.
To solve this problem, we can start by setting up equations based on the given information.
Let's assume Mari's present age is M, and Nandhini's present age is N.
According to the given information, Mari is 3 times older than Nandhini. So, we can write the equation:
M = 3N (Equation 1)
After ten years, the sum of their ages will be 80. So, we can write the equation:
(M + 10) + (N + 10) = 80 (Equation 2)
Now, we have two equations with two variables. We can solve these equations simultaneously to find the present age of Mari and Nandhini.
Substituting Equation 1 into Equation 2:
(3N + 10) + (N + 10) = 80
Simplifying the equation:
4N + 20 = 80
Subtracting 20 from both sides:
4N = 60
Dividing both sides by 4:
N = 15
Now, we substitute the value of N into Equation 1 to find M:
M = 3N
M = 3 * 15
M = 45
Therefore, the present age of Mari (M) is 45 years, and the present age of Nandhini (N) is 15 years.