how many grams of NaOh are needed to make 50 g of Na3PO4 according to the equation: 3NaOH+H3PO4=Na3PO4+3H2O

(i'm not sure where to even start for this!)

To determine the amount of NaOH needed to make 50 g of Na3PO4, we can use the molar ratios provided in the balanced chemical equation. Here are the steps to follow:

Step 1: Convert the given mass of Na3PO4 to moles.
To do this, you need to know the molar mass of Na3PO4. The molar mass of Na3PO4 is the sum of the atomic masses:
Na: 22.99 g/mol (sodium)
P: 30.97 g/mol (phosphorus)
O: 16.00 g/mol (oxygen)

Molar mass of Na3PO4 = (3 * Na) + P + (4 * O)
= (3 * 22.99 g/mol) + 30.97 g/mol + (4 * 16.00 g/mol)
= 163.94 g/mol

Next, calculate the number of moles of Na3PO4:
moles of Na3PO4 = mass of Na3PO4 / molar mass of Na3PO4

Given: mass of Na3PO4 = 50 g
moles of Na3PO4 = 50 g / 163.94 g/mol

Step 2: Use mole ratios from the balanced chemical equation.
According to the balanced equation, the mole ratio between NaOH and Na3PO4 is 3:1. This means that for every 3 moles of NaOH, 1 mole of Na3PO4 is produced.

moles of NaOH needed = moles of Na3PO4 * (3 moles of NaOH / 1 mole of Na3PO4)

Substitute the value of moles of Na3PO4 into the equation:
moles of NaOH needed = (50 g / 163.94 g/mol) * (3 moles of NaOH / 1 mole of Na3PO4)

Step 3: Convert moles of NaOH to grams.
To find the mass of NaOH required, multiply the moles of NaOH by its molar mass.

Molar mass of NaOH: Na = 22.99 g/mol, O = 16.00 g/mol, H = 1.01 g/mol
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol
= 39.00 g/mol

mass of NaOH needed = moles of NaOH * molar mass of NaOH

Substitute the value of moles of NaOH into the equation:
mass of NaOH needed = (moles of NaOH needed) * (molar mass of NaOH)

Now you can calculate the mass of NaOH needed.