17. neutralizing 20 ml 5.66% potassium hydroxide solution density of 1.053 g / cm3 matter 12.1 ml sulfuric acid density of 1.052 g / cm3. Determine the concentration (%) sulfuric acid solution.
Why did you flaunt the directions about typing your school subject in the above box?
How do you expect a chemistry expert to find your post?
Your post isn't clear to me at all. It appears you want to know the concn of the H2SO4 but the word "matter" in there makes no sense at all. Try rephrasing the question and this time proof what you've written. Thanks.
To determine the concentration of the sulfuric acid solution, you can use a simple calculation based on the volumes and densities of both solutions.
Step 1: Calculate the mass of the potassium hydroxide solution (KOH):
Mass = Volume × Density = 20 ml × 1.053 g/cm3 = 21.06 g
Step 2: Calculate the mass of the sulfuric acid solution (H2SO4):
Mass = Volume × Density = 12.1 ml × 1.052 g/cm3 = 12.74 g
Step 3: Calculate the moles of KOH in the potassium hydroxide solution using the molar mass of KOH (56.11 g/mol):
Moles of KOH = Mass of KOH / Molar mass of KOH = 21.06 g / 56.11 g/mol = 0.375 mol
Step 4: Determine the stoichiometric ratio of KOH to H2SO4 from the balanced chemical equation:
2 KOH + H2SO4 → K2SO4 + 2 H2O
The ratio is 2:1 for KOH to H2SO4, meaning that 1 mole of H2SO4 reacts with 2 moles of KOH.
Step 5: Calculate the moles of H2SO4 in the sulfuric acid solution:
Moles of H2SO4 = Moles of KOH / 2 = 0.375 mol / 2 = 0.1875 mol
Step 6: Calculate the concentration of the sulfuric acid solution as a percentage:
Concentration (%) = (Moles of H2SO4 / Volume of sulfuric acid solution) × 100
The volume of the sulfuric acid solution is 12.1 ml, which can be converted to liters:
Volume (L) = Volume (ml) / 1000 = 12.1 ml / 1000 = 0.0121 L
Concentration (%) = (0.1875 mol / 0.0121 L) × 100 = 1547.93%
Therefore, the concentration of the sulfuric acid solution is approximately 1547.93%.