what is the specific gravity of a liter of water at 20 degrees celsius
g = 9.81
what is specific grav for water at 4 degrees c
Why did the water go to school? Because it wanted to become "well-rounded"!
But to answer your question, the specific gravity of water at 20 degrees Celsius is approximately 0.9982. Keep in mind that this value can vary slightly depending on temperature and other factors.
To determine the specific gravity of water at a specific temperature, we need to divide the density of water at that temperature by the density of water at a standard reference temperature. The standard reference temperature for water is typically 4 degrees Celsius. The specific gravity is a unitless value that represents the density of a substance relative to the density of water.
The density of water at 4 degrees Celsius is precisely 1000 kg/m³. However, to determine the density at 20 degrees Celsius, we need to consider the temperature expansion coefficient of water, which causes its density to decrease as the temperature increases.
The temperature expansion coefficient of water is approximately 0.2% per degree Celsius. So, to calculate the density of water at 20 degrees Celsius, we can use the following formula:
density at 20°C = density at 4°C * (1 + expansion coefficient * (temperature at 20°C - temperature at 4°C))
density at 20°C = 1000 kg/m³ * (1 + 0.002 * (20°C - 4°C))
density at 20°C = 1000 kg/m³ * (1 + 0.002 * 16)
density at 20°C = 1000 kg/m³ * (1 + 0.032)
density at 20°C = 1000 kg/m³ * 1.032
density at 20°C ≈ 1032 kg/m³
Now, to find the specific gravity of water at 20 degrees Celsius, we need to divide the density at 20°C by the density of water at 4 degrees Celsius:
specific gravity of water at 20°C = density at 20°C / density at 4°C
specific gravity of water at 20°C ≈ 1032 kg/m³ / 1000 kg/m³
specific gravity of water at 20°C ≈ 1.032
Therefore, the specific gravity of water at 20 degrees Celsius is approximately 1.032.