Algebra
posted by Anonymous
The equation h= 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground,at t seconds after the ball is thrown upward.How many seconds after the ball is thrown will it reach its maximum height? What is its maximum height?

Damon
v = dh/dt = 32 32 t
at top, v = 0
t = 1
h = 9+16 = 25
======================
now with algebra
16 t^2 32 t =9  h
complete square
t^2 2 t = (1/16)(h  9)
t^22t+1 = (1/16)(h  9)+16/16
(t1)^2 = (1/16)( h25)
t = 1, h=25 same answer
Respond to this Question
Similar Questions

math
ball is thrown up at 88 ft/s from a height of 25 feet. Path of ball is y = 16t^2 + 88t +25. y is the height of ball above the ground t seconds after being thrown. when does it reach maxiumum height? 
Algebra
If a ball is thrown vertically upward from a height of 56ft. above ground with an initial velocity of 40ft. per second, then the height of the ball above ground t seconds after it is thrown is given by f(t)=16t^2 + 40t +56. How many … 
precalc
Physics: a ball is thrown vertically upward with an initial velocity of 80 feet per second. the distance (in feet) of the ball from the ground after t seconds if s=80t16tt^2 a) draw the illustration b) for what time interval is the … 
Math
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t16t^2 a.) at what time will the ball strike the ground b.) for what … 
physics
A red ball is thrown down with an initial speed of 1.2 m/s from a height of 25.0 meters above the ground. Then, 0.6 seconds after the red ball is thrown, a blue ball is thrown upward with an initial speed of 22.9 m/s, from a height … 
Physics
A red ball is thrown down with an initial speed of 1.3 m/s from a height of 28.0 meters above the ground. Then, 0.6 seconds after the red ball is thrown, a blue ball is thrown upward with an initial speed of 24.7 m/s, from a height … 
PreCalc
ball thrown vertically upward with an initial velocity of 80 ft per second. The distance s(in ft) of the ball from the ground after t seconds is s=80t16t^2. a. draw the illustration. b. for what time interval is ball more than 96 … 
Math
With s(t) measured in feet and t in seconds, the equation s(t)= 16t^2 + 32t expresses the height of a ball above the ground after t seconds if it were thrown upward with a velocity of 32 ft/sec. (a) What is the maximum height of the … 
Algebra 1
a ball is thrown into the air with an upward velocity of 32 ft per second. Its height h in feet after t seconds is given by the function h(t)=16t^2 +32t+6. How long does it take the ball to reach its maximum height? 
Algebra
The equation h = 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach its maximum height?