Take 1mL of 1M NaCl solution, and add 9mL of water. Then take 10microL of the diluted solution and add 40microL of water. What is the dilution? And what is the final concentration of NaCl?
So I see how this is a 2:1 dilution, but I am having a hard time figuring out the final concentration of NaCl. Any help? Thanks.
To calculate the final concentration of NaCl after dilution, we need to use the concept of dilution factor. The dilution factor is the ratio of the final volume to the initial volume.
In the first step, you took 1 mL of 1 M NaCl solution and added 9 mL of water. This results in a total volume of 1 mL + 9 mL = 10 mL.
Therefore, the dilution factor for the first step is 10 mL / 1 mL = 10.
In the second step, you took 10 μL of the diluted solution and added 40 μL of water. This gives a total volume of 10 μL + 40 μL = 50 μL.
Now, let's calculate the dilution factor for the second step. Since you started with 10 mL and ended with 50 μL, we need to convert the units to mL to have a consistent measurement.
50 μL is equal to 50/1000 mL = 0.05 mL.
The dilution factor for the second step is 0.05 mL / 10 mL = 0.005.
To find the overall dilution factor, multiply the dilution factors of each step together:
Overall dilution factor = Dilution factor of step 1 × Dilution factor of step 2 = 10 × 0.005 = 0.05.
The overall dilution factor is 0.05, which means the final volume is 0.05 times the initial volume.
Since the initial concentration was 1 M NaCl, the final concentration can be calculated by dividing the initial concentration by the overall dilution factor:
Final concentration = Initial concentration / Overall dilution factor = 1 M / 0.05 = 20 M.
Therefore, the final concentration of NaCl after the dilution is 20 M.
Note: The result, 20 M, is unrealistically high for a NaCl concentration. Please double-check your initial concentration value or the units provided.
To calculate the final concentration of NaCl, we can use the dilution formula:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given:
C1 = 1M (initial concentration)
V1 = 1mL (initial volume)
V2 = 10μL + 40μL = 50μL (final volume)
Let's calculate the final concentration (C2):
C1V1 = C2V2
1M * 1mL = C2 * 50μL
C2 = (1M * 1mL) / 50μL
However, before proceeding, we need to convert the volume to the same unit. Let's convert μL to mL:
1mL = 1000μL
Now the equation becomes:
C2 = (1M * 1mL) / 50μL * (1000μL/1mL)
C2 = (1M * 1) / (50*1000)
C2 = 0.02M
Therefore, the final concentration of NaCl is 0.02M.