Algebra
posted by Aaron .
The equation h = 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach its maximum height? What is its maximum height?

Algebra 
Reiny
find the vertex of the parabola.
The t of the vertex tells you when it reached the maximum height, the h tells you what that height is.
Respond to this Question
Similar Questions

math
ball is thrown up at 88 ft/s from a height of 25 feet. Path of ball is y = 16t^2 + 88t +25. y is the height of ball above the ground t seconds after being thrown. when does it reach maxiumum height? 
Algebra
If a ball is thrown vertically upward from a height of 56ft. above ground with an initial velocity of 40ft. per second, then the height of the ball above ground t seconds after it is thrown is given by f(t)=16t^2 + 40t +56. How many … 
math
A person standing on the roof of a building throws a ball directly upward. The ball misses the rooftop on its way down and eventually strikes the ground. The function s(t) = −16t2 + 64t + 80 describes the ball’s height above … 
PreCalc
ball thrown vertically upward with an initial velocity of 80 ft per second. The distance s(in ft) of the ball from the ground after t seconds is s=80t16t^2. a. draw the illustration. b. for what time interval is ball more than 96 … 
Math
With s(t) measured in feet and t in seconds, the equation s(t)= 16t^2 + 32t expresses the height of a ball above the ground after t seconds if it were thrown upward with a velocity of 32 ft/sec. (a) What is the maximum height of the … 
Algebra 1
A ball is thrown into the air with the in initial upward velocity of 45 ft/s. It's height (h) in feet after t seconds is given by the function h= 16t^2+45t+6. After about how many seconds will the ball hit the ground? 
College Algebra
Flight of a Ball If a ball is thrown upward at 96 feet per second from the top of a building that is 100 feet high, the height of the ball can be modeled by S(t)=100 + 96t 16t^2 feet, where t is the number of seconds after the ball … 
Algebra 1
a ball is thrown into the air with an upward velocity of 32 ft per second. Its height h in feet after t seconds is given by the function h(t)=16t^2 +32t+6. How long does it take the ball to reach its maximum height? 
Algebra
The equation h= 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground,at t seconds after the ball is thrown upward.How many seconds after the ball is thrown will it reach its maximum height? 
algebra
A ball is thrown into the air with an upward velocity of 40 feet per second. Its height, h, in feet after t seconds is given by the function h(t)=16t^2+40t+10. a. What is the ball’s maximum height?