Carbohydrates (such as C6H12O6) undergo combustion with oxygen to produce carbon dioxide and water. Living things use this reaction (a process called respiration) to produce energy.
Determine the mass of carbohydrates consumed for every 0.300 mol of oxygen gas consumed during respiration.
To determine the mass of carbohydrates consumed for every 0.300 mol of oxygen gas consumed during respiration, we need to use the balanced chemical equation for the combustion of carbohydrates.
The balanced equation for the combustion of carbohydrates is:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
From the equation, we can see that for every 6 moles of oxygen gas consumed, 1 mole of carbohydrates is consumed.
We are given that 0.300 mol of oxygen gas is consumed.
To find the moles of carbohydrates consumed, we can set up a ratio:
0.300 mol O2 : X mol carbohydrates
From the balanced equation, we know that the ratio of moles of O2 to moles of carbohydrates is 6:1. Therefore, we can set up the equation:
0.300 mol O2 / 6 mol O2 = X mol carbohydrates
Simplifying the equation gives us:
X = 0.300 mol O2 / 6 = 0.050 mol carbohydrates
Now, to find the mass of carbohydrates consumed, we need to multiply the moles by the molar mass of carbohydrates (C6H12O6). The molar mass of C6H12O6 can be calculated:
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Total molar mass of C6H12O6 = (6 * 12.01) + (12 * 1.01) + (6 * 16.00) = 72.06 + 12.12 + 96.00 = 180.18 g/mol
Finally, we can calculate the mass of carbohydrates consumed:
Mass = moles * molar mass
Mass = 0.050 mol * 180.18 g/mol = 9.01 grams
Therefore, for every 0.300 mol of oxygen gas consumed during respiration, approximately 9.01 grams of carbohydrates are consumed.