A bike wheel is spun until it reaches an angular velocity of 2.00 rad/s. It was spun for 1.96 s. What was its change in angle during this time if it started from rest?
V = Vo + a*t = 2.0 rad/s.
0 + a*1.96 = 2.0, a = 1.02 rad/s^2.
d = 0.5a*t^2 = 0.51*1.96*2 = 1.96 rad.
(360deg./6.28rad) * 1.96rad = 112.4 deg.
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To find the change in angle of the bike wheel, we can use the formula:
Δθ = ω * t
where Δθ is the change in angle, ω is the angular velocity, and t is the time.
In this case, the angular velocity is given as 2.00 rad/s and the time is given as 1.96 s.
Substituting these values into the formula, we can calculate the change in angle:
Δθ = 2.00 rad/s * 1.96 s
Δθ = 3.92 radians
Therefore, the change in angle of the bike wheel during this time is 3.92 radians.