Algebra 2
posted by Lewis .
One hundred liters of a 57.84% acid solution is obtained by mixing a 75% solution with a 42% solution. How many liters of each must be used to obtain the desired mixture?
A) 40 liters of 75% acid and 60 liters of 42% acid
B) 53 liters of 75% acid and 47 liters of 42% acid
C) 58 liters of 75% acid and 42 liters of 42% acid
D) 43 liters of 75% acid and 57 liters of 42% acid
E) 48 liters of 75% acid and 52 liters of 42% acid

.75 x + .42 y = .5784 (100)
x+y = 100
============================
.75 x + .42 y = 57.84
.75 x + .75 y = 75

.33 y =  17.16
y = 52
x = 48
E
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