How would I make a 93.1% w/w solution from 96% sulfuric acid using volume
To make a 93.1% w/w (weight/weight) solution from a 96% sulfuric acid solution using volume, you'll need to take into account the density of the sulfuric acid solution.
First, let's assume you want to make 100 grams of the 93.1% w/w solution.
Step 1: Determine the amount of sulfuric acid required
Since the 96% sulfuric acid solution is already given in percentage by weight, you can calculate the amount of sulfuric acid using the following formula:
Amount of sulfuric acid = (desired concentration / initial concentration) * total weight
Amount of sulfuric acid = (93.1 / 96) * 100 grams
Amount of sulfuric acid = 96.77 grams
So, you would need 96.77 grams of the 96% sulfuric acid solution.
Step 2: Determine the amount of water required
To know how much water is needed to dilute the sulfuric acid and achieve the desired concentration, subtract the amount of sulfuric acid from the total weight:
Amount of water = total weight - amount of sulfuric acid
Amount of water = 100 grams - 96.77 grams
Amount of water = 3.23 grams
Step 3: Convert weight to volume
Since we want to find the volume of each component, we need to convert the weights to volumes. To do this, we'll use the density of the sulfuric acid solution.
Density is defined as mass per unit volume, so we can rearrange the formula to calculate the volume:
Volume = mass / density
The density of sulfuric acid can vary depending on the concentration and temperature. For the purpose of this explanation, let's assume a density of 1.84 g/mL for the 96% sulfuric acid solution.
Volume of sulfuric acid = amount of sulfuric acid / density
Volume of sulfuric acid = 96.77 grams / 1.84 g/mL
Volume of sulfuric acid ≈ 52.62 mL
Volume of water = amount of water / density
Volume of water = 3.23 grams / 1 g/mL (since water has a density of approximately 1 g/mL)
Volume of water ≈ 3.23 mL
So, to make a 93.1% w/w solution from 96% sulfuric acid using volume, you would mix approximately 52.62 mL of the 96% sulfuric acid solution with approximately 3.23 mL of water.