normality of a solution containing 2g sodium carbonate in 250mL solution
Technically you can't do this without knowing the reaction. But USUALLY, when the reaction isn't know, one assume that one takes the molarity and multiplies by the total positive or negative charge.
mols Na2CO3 = grams/molar mass.
M = mols/L
N = M x 2.
To determine the normality of a solution, we need to know the number of moles of solute and the volume of the solution. Here's how you can find the normality of a solution containing 2 grams of sodium carbonate (Na2CO3) in 250 mL of solution:
Step 1: Calculate the number of moles of sodium carbonate (Na2CO3):
To calculate the number of moles, we need to use the formula:
moles = mass / molar mass
The molar mass of sodium carbonate (Na2CO3) is:
(2 × atomic mass of Na) + atomic mass of C + (3 × atomic mass of O)
= (2 × 22.99 g/mol) + 12.01 g/mol + (3 × 16.00 g/mol)
= 46.00 g/mol + 12.01 g/mol + 48.00 g/mol
= 106.01 g/mol
So, the number of moles of sodium carbonate is:
moles = 2 g / 106.01 g/mol
Step 2: Calculate the volume in liters (L):
Since the volume given is in milliliters (mL), we need to convert it to liters by dividing it by 1000.
volume = 250 mL / 1000 mL/L
Step 3: Calculate the normality (N) of the solution:
The formula to calculate normality is:
N = (moles of solute) / (volume of solution in liters)
Now, let's substitute the values into the formula:
N = (moles) / (volume)
N = (2 g / 106.01 g/mol) / (250 mL / 1000 mL/L)
N = (2 g / 106.01 g/mol) / (0.25 L)
Calculating this expression will give you the normality of the solution containing 2 grams of sodium carbonate in 250 mL solution.