81x^(6)-25y^(10) Factor
you have a difference of two squares a^2-b^2 = (a-b)(a+b)
where
a = 9x^3
b = 5y^5
Now just plug and chug.
To factor the expression 81x^6 - 25y^10, we can use the difference of squares formula, which states that a^2 - b^2 can be factored as (a + b)(a - b).
In this case, we have (81x^6 - 25y^10). Notice that 81x^6 can be written as (9x^3)^2 and 25y^10 can be written as (5y^5)^2.
Using the difference of squares formula, we can factor the expression as follows:
(9x^3)^2 - (5y^5)^2
Now, applying the difference of squares formula, we get:
(9x^3 + 5y^5)(9x^3 - 5y^5)
So, the factored form of 81x^6 - 25y^10 is (9x^3 + 5y^5)(9x^3 - 5y^5).