given that sin (90-5 t ta )=cos180 - t ta...find d value of t ta
What is "t ta" ??
Where does "d" enter the picture?
I will assume that by t ta you mean Ø
so sin(90 - 5Ø) = cos(180 - Ø)
but sin(90 - 5Ø) = cos Ø
just like sin(90 - 30) = cos30
so we have
cos(5Ø) = cos(180-Ø)
take arccos of both sides
5Ø = 180-Ø
6Ø = 180
Ø = 30
Ø is the math symbol called "theta"
It comes from the 8th letter in the Greek alphabet:
http://www.omniglot.com/images/writing/classical_attic.gif
To find the value of t ta, let's simplify the equation step by step:
1. Recall the trigonometric identity: sin (90° - θ) = cos θ.
Applying this identity, we can rewrite the left side of the equation as: cos (5 t ta).
2. Simplify cos(180° - θ):
It is known that cos (180° - θ) is equal to -cos θ. So, we have: -cos t ta.
Now our equation becomes:
cos (5 t ta) = -cos t ta
To solve for t ta, we will equate the arguments:
5 t ta = t ta
Now, let's solve for t ta:
Subtracting t ta from both sides:
5 t ta - t ta = 0
Combining like terms:
4 t ta = 0
Dividing both sides by 4:
t ta = 0
Therefore, the value of t ta is 0.