please what is the answer to this f math question......1-cos^2X=0 for 0°less dan equals X..then X less dan equals 270
1 - cos^2 x = 0 , for 0 ≤ x ≤ 270°
cos^2 x = 1
cos x = ± 1
now look at the cosine curve.
Where is the y equal to either +1 or -1 within your domain ?
1 - cos ^ 2 x = sin ^ 2 x
1 - cos ^ 2 x = 0 mean:
sin ^ 2 x = 0
take square root of both sides:
sin x = 0
On interval 0 ≤ x ≤ 270°
sin x = 0 only for x = 0
Correction.
On interval 0 ≤ x ≤ 270°
sin x = 0 only for x = 0 and x = 180°
To find the solution to the equation 1 - cos^2(X) = 0, we will apply basic algebraic techniques.
Step 1: Rearrange the equation to isolate cos^2(X):
cos^2(X) = 1
Step 2: Take the square root of both sides:
cos(X) = ±√1
Step 3: Simplify:
cos(X) = ±1
Since X is between 0° and 270°, we need to find the values of X that satisfy the equation cos(X) = ±1 within this range.
For cos(X) = 1, the values of X are 0°, 360°, 720°, etc. However, we need to consider the specified range, so the values between 0° and 270° are 0° and 180°.
For cos(X) = -1, the values of X are 180°, 540°, 900°, etc. Within the specified range, the value of X that satisfies this equation is 180°.
Therefore, the possible values for X that satisfy the equation 1 - cos^2(X) = 0 for 0° ≤ X ≤ 270° are 0° and 180°.