a man gives 40% of his money to his children and 20% of the remaining to a trust. if he is still left with rs.9600.what did he originally have?

20000

To find out the original amount of money the man had, we can work backwards from the information given.

Let's assume the man initially had X amount of money.

From the given information, we know that the man gives 40% of his money to his children. This means that he has (100% - 40%) = 60% of his money remaining.

Therefore, the remaining amount after giving money to his children is 60% of X, which is 0.6X.

Next, we are told that he gives 20% of the remaining amount to a trust. This means he has (100% - 20%) = 80% of the remaining amount left.

Therefore, the amount of money he has after giving money to his children and the trust is 80% of 0.6X, which is (0.8 * 0.6X) = 0.48X.

According to the given information, the man is still left with Rs. 9600, which is equal to 0.48X.

So, we can set up the equation: 0.48X = 9600.

To find X, we can solve for X by dividing both sides of the equation by 0.48: X = 9600 / 0.48 = Rs. 20,000.

Therefore, the man originally had Rs. 20,000.

so he gave away 60%, leaving him with 40%

.4x = 9600

solve for x

24000