An empty SG bottle weights 25 g.When filled with water completely it weights 55 g and with alcohol it weights 48 g. Find the RD of alcohol
A numerical
V = (55-25)g * 1cm^3/g = 30 cm^3.
Da = M/V = (48-25)g/30cm^3 = 0.767 g/cm^3 = Density of alcohol.
To find the relative density (RD) of alcohol, we need to compare its density to that of water.
The formula for relative density is:
RD = density of substance / density of reference substance
In this case, the reference substance is water because the weight of the bottle filled with water is given.
We are given the weight of the empty bottle, which is 25 grams. When filled with water, the weight is 55 grams. So, the weight of water in the bottle is 55 grams - 25 grams = 30 grams.
Given that the density of water is 1 g/cm³ (or 1000 kg/m³), we can calculate the RD of alcohol as follows:
RD of alcohol = (weight of alcohol) / (weight of water)
Since the weight of the bottle filled with alcohol is 48 grams, the weight of alcohol is 48 grams - 25 grams = 23 grams.
RD of alcohol = 23 grams / 30 grams = 0.7667
Therefore, the relative density of alcohol is approximately 0.7667.