the top of a rectangular table has a length that is two times it's width. The perimeter of the tabletop is 144 inches. What is the width of the tabletop?
P = 2L + 2W
144 = 2(2W) + 2W
144 = 6W
24 = W
Let's assume the width of the tabletop is 'w' inches.
According to the given information, the length of the tabletop is two times its width, so the length would be 2w inches.
The perimeter of a rectangle is given by the formula:
Perimeter = 2(length + width)
Given that the perimeter of the tabletop is 144 inches:
144 = 2(2w + w)
Now, let's solve for 'w':
144 = 2(3w)
144 = 6w
Divide both sides of the equation by 6:
144/6 = 6w/6
24 = w
Therefore, the width of the tabletop is 24 inches.
To find the width of the tabletop, we can set up a system of equations based on the given information.
Let's say the width of the tabletop is represented by "w" inches. Since the length is two times the width, we can say that the length is 2w inches.
The perimeter of a rectangle can be calculated by adding up all four sides. In this case, the perimeter is given as 144 inches, so we can write the equation:
Perimeter = 2(length + width)
Substituting the values we know, we have:
144 = 2(2w + w)
To solve this equation, we can simplify it:
144 = 2(3w)
Divide both sides of the equation by 2:
72 = 3w
Finally, divide both sides by 3:
w = 24
Therefore, the width of the tabletop is 24 inches.