Hydrogen gas is used for many purposes, including the hydrogenation of vegetable oils to make margarine. The most common industrial process for producing hydrogen is "steam reforming", in which methane gas, CH4, from natural gas reacts with water vapor to form carbon monoxide gas and hydrogen gas.

Write a complete balanced equation, including states, for this reaction.

Write a conversion factor that could be used to convert moles of methane and mole of hydrogen.

How many moles of hydrogen from when 10 moles of methane react completely?

How many moles of water vapor react to yield 546.234 moles of hydrogen?

To write a balanced equation for the steam reforming process, we need to ensure that the number of atoms on both sides of the equation is equal.

The balanced equation for the reaction between methane and water vapor is:

CH4 (g) + H2O (g) ---> CO (g) + 3H2 (g)

To write a conversion factor for moles of methane and moles of hydrogen, we can use the balanced equation. From the equation, we can see that for every mole of methane, we get 3 moles of hydrogen. So the conversion factor is:

1 mole CH4 : 3 moles H2

Now let's answer the given questions:

1. When 10 moles of methane react completely, we can use the conversion factor to calculate the moles of hydrogen produced.

10 moles CH4 * 3 moles H2 / 1 mole CH4 = 30 moles H2

Therefore, 10 moles of methane would produce 30 moles of hydrogen.

2. To determine how many moles of water vapor are needed to produce 546.234 moles of hydrogen, we can rearrange the conversion factor as follows:

546.234 moles H2 * 1 mole CH4 / 3 moles H2 = 182.078 moles CH4

Thus, 182.078 moles of water vapor would react to yield 546.234 moles of hydrogen.

The balanced equation for the reaction is as follows:

CH4(g) + H2O(g) → CO(g) + 3H2(g)

A conversion factor can be derived from the balanced equation. From the equation, it can be seen that for every 1 mole of methane (CH4) that reacts, 3 moles of hydrogen (H2) are produced.

Therefore, the conversion factor is:

3 moles H2 / 1 mole CH4

To find the number of moles of hydrogen formed when 10 moles of methane react completely, we can use the conversion factor:

10 moles CH4 * (3 moles H2 / 1 mole CH4) = 30 moles H2

So, when 10 moles of methane react completely, 30 moles of hydrogen is produced.

To determine the number of moles of water vapor required to yield 546.234 moles of hydrogen, we can rearrange the conversion factor:

1 mole CH4 / 3 moles H2

Then, we can use this conversion factor to calculate the moles of water vapor:

546.234 moles H2 * (1 mole CH4 / 3 moles H2) = 182.078 moles H2O

So, 182.078 moles of water vapor react to yield 546.234 moles of hydrogen.

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