5. Suppose a skydiver (mass = 75 kg) is falling toward the Earth. When the skydiver is 100 m above the Earth he is moving at 60 m/s. At this point calculate the skydiver’s…….

Incomplete.

wats the answeerrrrr

To calculate the skydiver's velocity when he reaches the Earth, we need to use the principles of physics involving motion.

First, let's determine the potential energy of the skydiver. The potential energy is given by the formula:

Potential Energy = mass * acceleration due to gravity * height

In this case, the mass of the skydiver is 75 kg, the acceleration due to gravity is approximately 9.8 m/s^2, and the height is 100 m.

Potential Energy = 75 kg * 9.8 m/s^2 * 100 m = 73,500 Joules

Now, let's calculate the kinetic energy of the skydiver. The formula for kinetic energy is:

Kinetic Energy = 0.5 * mass * velocity^2

In this case, the mass of the skydiver is still 75 kg, and the velocity is given as 60 m/s.

Kinetic Energy = 0.5 * 75 kg * (60 m/s)^2 = 135,000 Joules

Since energy is conserved, the potential energy at the top is equal to the kinetic energy at the bottom (ignoring air resistance). Therefore:

Potential Energy at the top = Kinetic Energy at the bottom

73,500 Joules = 0.5 * 75 kg * (Velocity at the bottom)^2

We can rearrange the equation to solve for the velocity at the bottom:

(Velocity at the bottom)^2 = (73,500 Joules * 2) / 75 kg

Velocity at the bottom = sqrt((73,500 Joules * 2) / 75 kg)

Calculating this value gives us:

Velocity at the bottom ≈ 38.4 m/s

Therefore, when the skydiver reaches the Earth, his velocity will be approximately 38.4 m/s.