Mohit put 6 red balls and 7 black balls into a bag. What fraction of the balls are red balls?
6/(6+7)
To find the fraction of red balls in the bag, we first need to calculate the total number of balls in the bag.
Given that Mohit put 6 red balls and 7 black balls into the bag, the total number of balls in the bag is 6 + 7 = 13.
Now, let's find the fraction of red balls. The fraction of red balls can be calculated by dividing the number of red balls by the total number of balls.
So, the fraction of red balls is 6/13.
Therefore, the fraction of red balls in the bag is 6/13.