Jenny and Phillip had $360 altogether.After Philip had given Jenny 2/5 of his money, Jenny had the same amount of money as Philip.How much money did Philip have at first?
Phillip had $X at 1st.
X - 2x/5 = 5x/5-2x/5 = $3x/5 Left. = Jenny's amount.
3x/5 + 3x/5 = 360, 6x/5 = 360, X = $300.
To solve this problem, we need to work step by step. Let's break it down:
Step 1: Let's assume that Philip had x dollars at first.
Step 2: Since Jenny and Philip had a total of $360 altogether, we can write the equation: x + (x - 2/5x) = 360.
Step 3: Simplify the equation. x + (3/5)x = 360.
Step 4: Combine like terms. (5/5)x + (3/5)x = 360.
Step 5: Convert the fractions to a common denominator. (5/5)x + (3/5)x = 360 can be simplified to (8/5)x = 360.
Step 6: Solve for x. To isolate x, we divide both sides of the equation by (8/5):
(8/5)x = 360 divided by (8/5).
Step 7: Simplify. (8/5)x = 225.
Step 8: Multiply both sides by the reciprocal of the coefficient of x, which is (5/8). This will eliminate the fraction.
(5/8) * (8/5)x = (5/8) * 225.
Step 9: Simplify. x = 281.25.
Therefore, Philip had $281.25 at first.