How many Cu+2 ions are in 5.33 mol of CuCl2?
I did this so far:
n-> 5.33 mol Ncu-> ? ions
M= 134.45 g
=5.33 mol x (602x10^23 ions/ 1 mol)
=3.21x10^24 ions
you are correct
Why did the copper ion go to therapy?
Because it felt it had lost its cation-ship!
But let's get serious for a moment. The formula CuCl2 tells us that for every CuCl2 molecule, there are two Cu+2 ions present.
So, if you have 5.33 mol of CuCl2, you would have double the number of Cu+2 ions.
Therefore, the number of Cu+2 ions in 5.33 mol of CuCl2 would be 2 times 5.33 mol, which is 10.66 mol.
However, it seems you have already correctly converted this into the number of ions, which is approximately 3.21x10^24 ions. Well done!
To find the number of Cu+2 ions in 5.33 mol of CuCl2, you need to consider that there is one Cu+2 ion for every molecule of CuCl2.
Since the molar mass of CuCl2 is 134.45 g/mol, you have correctly calculated the number of moles:
n = 5.33 mol
To find the number of Cu+2 ions, you can use Avogadro's number (6.022 x 10^23 ions/mol), which represents the number of particles in one mole.
Ncu = n x (6.022 x 10^23 ions/mol)
= 5.33 mol x (6.022 x 10^23 ions/mol)
= 3.21 x 10^24 ions
Therefore, there are approximately 3.21 x 10^24 Cu+2 ions in 5.33 mol of CuCl2.
To determine the number of Cu+2 ions in 5.33 mol of CuCl2, you can use Avogadro's number and the stoichiometry of the compound.
1. Start by calculating the molar mass of CuCl2. Copper (Cu) has an atomic mass of 63.55 g/mol, and chlorine (Cl) has an atomic mass of 35.45 g/mol. Multiply the atomic mass of Cu by 1 since there is 1 Cu atom in CuCl2, and multiply the atomic mass of Cl by 2 since there are 2 Cl atoms in CuCl2.
Molar mass of CuCl2 = (63.55 g/mol x 1) + (35.45 g/mol x 2) = 134.45 g/mol
2. Next, calculate the number of moles of Cu+2 ions. Since there is one Cu+2 ion in each CuCl2 molecule, the number of moles of Cu+2 ions is the same as the number of moles of CuCl2.
Number of moles of Cu+2 ions = 5.33 mol
3. Use Avogadro's number (6.022 x 10^23 ions/mol) to convert moles of Cu+2 ions into the number of ions.
Number of ions = 5.33 mol x (6.022 x 10^23 ions/mol) = 3.21 x 10^24 ions
Therefore, there are approximately 3.21 x 10^24 Cu+2 ions in 5.33 mol of CuCl2.