From M1V1=M2V2 the volume of the KHP solution the molarity of the titrant and the volume of the titrant, find the molarity of the KHP solution . The KOH solution is the titrant since it is used to titrate the KHP solution.
KHP mass-204.2
Mass per liter in 100 ml water-
.01(204.2)/1= 2.042
Drop ml-20
Volume of titrant is 1.0/20=.05
I'm sorry but I can't decipher this post. I see you want the molarity of the KHP solution but "mass per liter in 100 mL water" and "drop ml-20" don't mean anything to me.
To find the molarity of the KHP solution using the given information, we can use the formula M1V1 = M2V2.
Given:
M1 = molarity of KHP solution
V1 = volume of KHP solution
M2 = molarity of the titrant (KOH solution)
V2 = volume of the titrant
We are given the following values:
M2 = molarity of the titrant = ?
V2 = volume of the titrant = 0.05 L
Let's substitute these values into the formula and solve for M1.
M1 * V1 = M2 * V2
Since we are solving for M1 (molarity of KHP solution), let's rearrange the formula:
M1 = (M2 * V2) / V1
Now let's substitute the known values into the formula:
M1 = (M2 * 0.05) / V1
However, we are missing the volume of the KHP solution (V1). It is not provided in the given information.
To find the molarity of the KHP (potassium hydrogen phthalate) solution, you can use the formula M1V1 = M2V2, where M1 is the molarity of the KHP solution, V1 is the volume of the KHP solution, M2 is the molarity of the titrant (KOH solution), and V2 is the volume of the titrant.
From the given information:
Mass of KHP = 204.2 g
Mass per liter in 100 ml of water = 0.01(204.2) / 1 = 2.042 g
You also mentioned that the volume of the titrant is 1.0 ml, and the drop size is 20 drops.
Now, let's proceed to find the molarity (M2) of the titrant (KOH solution):
First, convert the volume of the titrant from drops to liters:
Volume of titrant = 1.0 ml * (1 drop / 20 drops) = 0.05 L
Now, plug the values into the equation M1V1 = M2V2:
M1 * V1 = M2 * V2
Since we want to find M1 (molarity of the KHP solution), rearrange the equation to solve for M1:
M1 = (M2 * V2) / V1
Substitute the values:
M1 = (M2 * 0.05 L) / V1
At this point, you didn't mention the volume of the KHP solution (V1). If you provide that value, you can substitute it to find the molarity of the KHP solution (M1).
Therefore, to find the molarity of the KHP solution, you need to know the volume of the KHP solution and substitute it into the equation M1 = (M2 * 0.05 L) / V1.