If 300gm water of 25°c is added into 100gm ice of 0°c then calculate the final value if this mixture.
400gm 12.5c
0c
To calculate the final temperature of the mixture, we need to use the principle of energy conservation, specifically the principle of heat transfer.
Step 1: Calculate the heat absorbed by the ice during melting:
Q_ice = mass_ice * specific_heat_capacity_ice * change_in_temperature_ice
Q_ice = 100g * 2.09 J/g°C * (0°C - (-0°C))
Q_ice = 100g * 2.09 J/g°C * 0°C
Q_ice = 0 J
Since the temperature of the ice remains constant during phase change (melting), no heat is absorbed or released during this process.
Step 2: Calculate the heat released by the water during cooling:
Q_water = mass_water * specific_heat_capacity_water * change_in_temperature_water
Q_water = 300g * 4.18 J/g°C * (25°C - 0°C)
Q_water = 300g * 4.18 J/g°C * 25°C
Q_water = 3135 J
Step 3: Calculate the final temperature of the mixture:
The total heat gained by the mixture is equal to the heat released by the water:
Q_total = Q_water = 3135 J
Assuming no heat loss to the surroundings, the heat gained by the water is equal to the heat lost by the ice. Therefore, the total heat gained by the mixture is zero:
Q_total = Q_ice + Q_water
0 J = 0 J + 3135 J
Since the heat gained is zero, the final temperature of the mixture is also zero degrees Celsius (0°C).
Therefore, the final value of the mixture is 0°C.