what kind of reaction is this Sr(NO3)2 (aq) + K2CrO4 (aq) = SrCrO4 (S) + 2KNO3 (aq) and does it take place or NR, why?
Ah, chemistry, the field that always makes reactions happen, or sometimes not! In this case, we have Sr(NO3)2 (aq) + K2CrO4 (aq) giving us SrCrO4 (S) + 2KNO3 (aq). Now, let's break it down.
The reaction you provided is a classic example of a double displacement reaction, also known as a "precipitation reaction." It involves the exchange of ions between two compounds, resulting in the formation of a solid precipitate.
In this case, Sr(NO3)2 (aq) and K2CrO4 (aq) are mixed together, and the cations and anions of the reactants switch partners. Sr (strontium) combines with CrO4 (chromate) to form the solid precipitate SrCrO4, while K (potassium) joins forces with NO3 (nitrate) to yield the soluble compound KNO3.
So, to answer your question, the reaction does take place. However, if you're wondering about the "NR" part, well, that's a big "No Reaction" here. When it comes to chemical reactions, sometimes they happen, sometimes they don't, and sometimes they just want to take a nap. But in this case, we have a lovely precipitation reaction going on!
I hope I managed to bring a little bit of chemistry amusement to your day!
The reaction you provided is a double replacement or double displacement reaction. In this type of reaction, the cations (+ charged ions) and anions (- charged ions) in the reactants switch places to form new compounds.
In this case, Sr(NO3)2 (aq) + K2CrO4 (aq) react to produce SrCrO4 (s) (strontium chromate) and 2KNO3 (aq) (potassium nitrate).
Whether the reaction takes place or not depends on the solubility of the resulting compounds. If at least one of the products is insoluble or forms a solid precipitate, the reaction will occur. The solubility of the compounds can be determined using solubility rules.
Using the solubility rules, we can see that SrCrO4 is insoluble or forms a solid precipitate, while KNO3 is soluble in water. Therefore, the reaction will take place, and the products will be SrCrO4 (s) and 2KNO3 (aq).
The given chemical equation represents a double displacement reaction, also known as a precipitation reaction.
To determine if the reaction will take place or not, we need to check if a precipitation (solid) forms. In this case, Sr(NO3)2 (aq) and K2CrO4 (aq) are the reactants, and SrCrO4 (s) and 2KNO3 (aq) are the products.
To identify whether a precipitate is formed or not, we need to refer to the solubility rules. These rules provide information about the solubility of different compounds in water.
According to the solubility rules, most nitrates (NO3-) and potassium compounds (K+) are soluble in water and do not form a precipitate. Therefore, KNO3 (aq) is soluble and stays in the solution as ions.
However, strontium chromate (SrCrO4) is insoluble and forms a yellow precipitate. Therefore, SrCrO4 (s) is formed during the reaction.
Thus, the reaction is a double displacement reaction where a precipitate is formed as one of the products.
Overall equation: Sr(NO3)2 (aq) + K2CrO4 (aq) → SrCrO4 (s) + 2KNO3 (aq)