Please tell me if my awsers are correct

A picture frame is 12 inches long and 9 inches wide. In inches, what is the diagonal length of the picture frame?

A)21inches

I already answered this for you. Why did you change your answer?

Use the Pythagorean theorem, which is: a squared + b squared = c squared

So that is 12x12 + 9x9 = c x c
or 144 + 81 = c x c
to solve add 144+81= 225
Take the square root of 225 which equals 15

Your answer is the diagonal (or hypotenuse) equals 15

Oh, by the way, Steve?

You're a moron, don't attempt to help if you're clueless.
I realize of course Pear, that this doesn't help you, hopefully it will help someone else.

To find the diagonal length of a rectangle, you can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.

In this case, the length and width of the picture frame form the two sides of a right triangle, and the diagonal is the hypotenuse. The length is 12 inches, and the width is 9 inches.

To find the diagonal length, we can use the formula:

diagonal^2 = length^2 + width^2

diagonal^2 = 12^2 + 9^2
diagonal^2 = 144 + 81
diagonal^2 = 225

Now, we can find the square root of 225 to get the diagonal length:

diagonal = √225
diagonal = 15 inches

Therefore, the correct answer is B) 15 inches.

Not so. Think about your answer. 9+12=21

Those cannot be the sides of a triangle. The 9 and 12 sides would have to lie completely flat on top of the 21 side.

The third side must be less than 9+12. In fact, if the 3rd sides is x,

12-9 < x < 12+9