posted by james .
In a similar experiment, a sample of tin metal was dissolved in nitric acid to produce 23.00 mL of solution containing Sn2+. Titration analysis resulted in the calculation that the concentration of Sn2+ in this solution was 0.65 mol/L.
b. What mass of tin was used to make the tin solution?
Since Sn ==> Sn^2+, then if M Sn^2+ is 0.65, so mols Sn^2+ = M x L = 0.65 x 0.023 = ? and same mols Sn to have started the process.
Then g Sn = mols Sn x atomic mass Sn = ?