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Commercial Sodium hydroxide has a concentration of 19.4mol/L. How many milliliters of sodium hydroxide solution can be prepared from 59g or sodium hydroxide.

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    Your post just isn't clear. I can prepare almost any number of mL from 59 g NaOH but of WHAT concentration. Do you mean to start with 59 g NaOH and ask how many mL of 19.4M NaOH can be prepared from that? If so then
    mols NaOH in 59 g = grams/molar mass = 59/40 = 1.475 mols NaOH.
    Then M NaOH = mols NaOH/L NaOH
    19.4 = 1.475/L and solve for L the convert to mL.

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