A solution contains 0.100 mg of NaOH dissolved in enough water to make 10.0 L of solution.

whats the concentration

given: 0.100mg NaOH.


adding water to make
10.0Liters.

Find : Molarity

Molarity (M)= Moles solute
---------------
Liters of Solution

mol NaOH=0.100g NaOH
multiply
1 mol NaOH
-----------
40 g NaOH
equals= .0025 mol NaOH

Molarity (M) = Moles of solute devided by liters of solution

.0025/10.0L solution= 2.5times ten^ to the negative 4

To find the concentration of the NaOH solution, we need to calculate the molarity (M) of the solution.

Molarity (M) is defined as the number of moles of solute per liter of solution.

First, we need to determine the number of moles of NaOH present in the solution.

Given:
Mass of NaOH = 0.100 mg = 0.0001 g
Volume of solution = 10.0 L

The molar mass of NaOH can be found using the periodic table:
Na (sodium) = 22.99 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol

Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

Now, we can calculate the number of moles of NaOH:
Number of moles = Mass / Molar mass
Number of moles = 0.0001 g / 40.00 g/mol

Next, we calculate the molarity:
Molarity = Number of moles / Volume of solution
Molarity = [0.0001 g / (40.00 g/mol)] / 10.0 L

Molarity = 2.50 x 10^-5 mol/L

Therefore, the concentration of the NaOH solution is 2.50 x 10^-5 mol/L.

To find the concentration of a solution, we need to know the amount of solute (in this case, NaOH) and the volume of the solution it is dissolved in.

Given information:
Amount of NaOH = 0.100 mg
Volume of solution = 10.0 L

Concentration is usually expressed in terms of moles per liter (molarity). To calculate the concentration (in moles per liter), we need to convert the given amount of NaOH into moles.

First, we need to convert the amount of NaOH from milligrams to grams:

0.100 mg = 0.100 × 10^(-3) g = 0.0001 g

Next, we need to convert grams of NaOH to moles using the molar mass of NaOH. The molar mass of NaOH is:
Na (Sodium) = 22.99 g/mol
O (Oxygen) = 16.00 g/mol
H (Hydrogen) = 1.01 g/mol

So, molar mass of NaOH = (22.99 + 16.00 + 1.01) g/mol = 39.00 g/mol

Now we can calculate the number of moles of NaOH:
moles of NaOH = mass (in grams) / molar mass (in g/mol)
moles of NaOH = 0.0001 g / 39.00 g/mol

Once we have the number of moles of NaOH, we can calculate the concentration using the given volume of solution:

Concentration (in moles per liter) = moles of NaOH / volume of solution (in liters)
Concentration = (0.0001 g / 39.00 g/mol) / 10.0 L

Calculating this expression gives us the concentration of NaOH in the solution.